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2014-08-23T15:07:57+05:30

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R = resistance at t = 0sec

R' = R - 0.1 * \frac{n}{10} = R - 0.01 n \\  
R' is    resistance at n = 1 sec
I = \frac{V}{R'} = \frac{120}{R - 0.01 n} \\

When R and R' are large, we can write:

I = 120 \frac{[ 1 + \frac{0.01 n}{R} ]}{R} \\ \\ \frac{120}{R} + \frac{1.2}{R^{2}} * n     is the current at nth second.

it is arith progr.  with first term and difference as shown in the above equation.
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