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Factor of ax^4+2x³-3x²+bx-4 is (x²-4) or (x-2)(x+2) so the value of the given equation is zero at x = 2 and x = -2, on putting the value of x = 2 16a+16-12+2b-4 = 0 16a+2b = 0 8a+b = 0 ---------------(1) on putting the value of x = -2 16a-16-12-2b-4 = 0 16a-2b = 32 8a-b = 16 -----------------(2) (1) + (2) 16a = 16 a = 1 put a = 1 in equation (1) we get b = -8 I hope you can understand .

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X²-4 = (x-2)(x+2) roots are 2 , -2 So divide by 2, and -2

| a 2 -3 b -4 | 2 | 2a 4+4a 2+8a 2b+16a+4 | ____________________________________ | a 2+2a 1+4a b+8a+2 2b+16a