Find the general solution of tan2Ѳ + ( 1- root3 ) tanѲ - root3 = 0

2
is it tan(2A) or tan^2(A), means tan_square_theta or tan_2_theta , what's the first term, i guess it's tan_2_theta
its tan square theta...
for next tym, write any squared term as tan^2(a)... like this
I answered it right then
k...

Answers

2014-08-23T19:52:31+05:30
See image.....I solved on paper.
1 4 1
u hv to find theta, general soln
M done with first term of c
Lass 10 and I still don't understand the term. General solution.
I did not find it nywhere
Sorry
2014-08-23T20:16:01+05:30
tan^2(\theta) + (1 -  \sqrt{3}) tan(\theta) -  \sqrt{3} = 0 \\ tan^2(\theta) + tan(\theta) - \sqrt{3} tan(\theta) -  \sqrt{3} = 0  \\ tan(\theta)(tan(\theta) + 1) -  \sqrt{3}(tan(\theta) + 1) = 0 \\ (tan(\theta) + 1)(tan(\theta)  -  \sqrt{3} ) = 0 \\ tan(\theta) = (-1,  \sqrt{3}) \\  \\ \theta =  (\frac{3 \pi }{4},  \frac{ \pi }{3})

So general Solution
\theta = (n \pi +  \frac{3 \pi }{4}, n \pi -  \frac{3 \pi }{4}, n \pi +  \frac{\pi }{3}, n \pi -  \frac{\pi }{3})
0
Hey, can u tell me what is general solution??
the value of sin of (30, 390, 750, 1110, ...) all is equal to 1/2. so if i say solve sin(a) = 1/2, then a = 30 is one solution, but all the other solutions can't be written coz they are countably infinite, but you can say a = n * 360 + 30, and n = 0, 1, 2, 3, ....... Now this is general solution ....