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Let Ф1 and Ф2 be the values of angles of projection such that the horizontal range of the projectile in both cases is equal. Then

A) Ф1 = Ф2
B) Ф1 + Ф2 = π/2
C) Ф1 + Ф2 = π/4
D) Ф1 - Ф2 = π/4
answer should come A) AND B)



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R = u² Sin 2 Ф / g

So Sin 2Ф1 = Sin 2Ф2

2Ф1 = 2Ф2  or  2Ф1 = 180 - 2Ф2 

Ф1 = Ф2  or  Ф1 = 90 - Ф2 

2 5 2
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