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A crime suspect passes an intersection in a car travelling at 110 mi/hr. the police pass the intersection 3.0 min later in a car traveling at 135 mi/hr.

how long is it before the police overtake the suspect?



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Relative speed of the police car with respect to criminal's car:
    135 - 110 = 25 mi/hr = 5/12 mile/minute

we can treat as if criminal car is stationary and police car is going at above speed.

Distance of criminal's car from junction when police car is at junction:
       3 min * 110 miles / 60min = 5.5 miles

time to cover this distance =  5.5 / (5/12) = 13.2 minutes

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