Answers

2014-08-24T14:47:08+05:30
Here, sec x \frac{1}{cosx} ;
now, cosx \frac{1}{secx} ;
then,  \frac{1}{secx} X  \frac{1}{x} =  \frac{1}{ sec^{2}x } . It may be wrong but see if there is hope.
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