Answers

2014-03-02T07:57:04+05:30
The point will be (0,y). x is zero since it's on the y-axis
Use Pythagoras:
d1^2 = (-2-0)^2 + (5-y)^2
d2^2 = (2-0)^2 + (-3 -y)^2
The two expressions are equal, so
4 + (5-y)^2 = 4 + (-3-y)^2
25 -10y +y^2 = 9 + 6y + y^2
16= 8y
y = 2
The point is (0,2)
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2014-03-02T13:33:48+05:30
Let first co-ordinate be as A co-ordinate and second be as B
ab=ac
root of  (-2-0)sq + (s-y)sq=root of (2-0)sq + (-3-y)sq
4+25+Ysq - 20y=4+9+Ysq+6y
25-10y=6y+9
therefore y=1
co-ordinate point on y-axis is (0,1)
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