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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

In a circle , a chord 3 centimeters away from the center is 8 centimeters long . how long is a chord ,1.4 centimeters away from the center in the circle ?

Let chord 8cm long meet the circle at at points A , B. Let Perpendicular from centre,say O, meet the above chord at C. Point C divides AB in two equal parts at C,i.e., AC = BC. Join OA. Then Triangle ACO have sides 4cm, 3cm and radius r. Then Radius = √(4² + 3²) = 5.

Now draw a chord 1.4cm from centre O. Let this chord meet circle at points D, E. Let perpendicular 1.4cm long meet chord DE at F. Join OD which is = radius = 5. Now in triangle ODF, OD = 5, OF = 1.4 . Hence DF = √(OD² - OF²) = √(5² - 1.4²) = 4.8. Hence length of the chord = 2x4.8 = 9.6cm Complete triangle

AB = 8 cm Since OM bisects AB Therefore, AM = BM = 4 cm In the right triangle OMA OM = 3 cm, AM = 4 cm Therefore, by Pythagorean theorem, OA = 5 cm That is, the radius of the circle = 5 cm

Now, ON = 1.4 cm Let CN = x cm By pythagorean theorem

x = 4.8

Therefore, the length of the chord CD = 2x = 9.6 cm