Answers

2014-03-10T18:53:17+05:30
Mass of  CaCO₃ in 200 grams of 90% pure calcium carbonate is 180 grams
no. of moles of CaCO₃ in 180 grams of CaCO₃ is 180/100=1.8 moles

so, 1.8 moles each of CaO and CO₂ are formed by Decomposition of 1.8 moles of CaCO₃.

CaCO₃------------Δ------------->>> CaO + CO₂

mass of 1 mole CaO is 56 grams
mass of 1.8 moles of CaO is 56*1.8=100.8 grams
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