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2014-08-27T04:40:17+05:30

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sin^2\ 5\ +\ sin^2\ 85\ =\ sin^2\ 5 + cos^2\ (90-85)\ =\ sin^2\ 5 + cos^2\ 5\ =\ 1 \\ \\

so we have pairs: 5,85; 10,80, .... 40,50;  and only one sin² 45 and one sin² 90

So the

Sum = 8 * 1 + (\frac{1}{\sqrt{2}})^2 + 1^2 = 9 \frac{1}{2}
1 5 1
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