A particle travels along the X axis such that in 5 sec, it moves purely rightwords from x = -8 m to x = +3 m. Then, in the next 5 seconds, it moves purely leftwords to x = -6 m. The particle's average velocity and average speed during the 10 seconds interval will be respectively:

( answer should come 0.2 m/sec and 2 m/sec )

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2014-08-28T01:56:23+05:30

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In the first 5 seconds, its speed = distance covered / time duration
                     =[ 3 - (-8) ] /  5  = 11/5 m/s
next five seconds average speed = abs( - 6 - 3 ) / 5 = 9/5 = 1.8 m/s

In the 10 seconds, velocity = net displacement / time duration
       = final - initial  = -6 - (-8) = 2 m
average velocity = 2m/10sec = 0.2 m/s

average speed in 10 sec = total distance traveled / time
             11 m to right + 9m to left  = 20 m / 10 sec = 2 m/s

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