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In Triangle ABC, D is the mid point of AB, E is any point of BC. CF (parallel to) ED meets AB at F. Show that (area of)Triangle BEF = 1/2 (area of)

Triangle ABC


By mid point formula we know that line joining mid point of triangle is parrel to other and half of it's length. This implies lenght og Ef = 1. And of other 2 
this implies area is 1:4or 1/2(as area is double of one side)
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