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If two bodies having masses 25kg and 20gm are placed at 20cm distance find the force between them given G= 6.67*10 MINUS RAISE TO POWER 11 N-m square/kg



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Force = \frac{GMm}{d^2} \\ \\ = 6.67 * 10^{-11} * \frac{25*20*10^{-3}} {0.2^2} = 8.3 * 10^{-10} Newtons \\
2 5 2
Given, m1=25kg
distance, r= 20cm=(20/100)m= 0.2m
G=6.67*10^{-11} Nm^2 kg^{-2}
We know, F=G \frac{m_1*m_2}{r^2}
Substituting the values of m1,m2,G & r
F= \frac{6.67*10^{-11}*25*0.02}{(0.2)^2}
F=83.375*10^{-11} N
F=8.3375*10^{-10} N
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