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The radius of the circle with centre at the origin is 10 units. Write the coordinates of the point where the circle intersects the axes. Find the distance

THE POINTS OF INTERSECTION ARE (10,0),(0,10),(-10,0) & (0,-10). THE DISTANCE BETWEEN ANY TWO OF THESE POINTS IS SQUARE OF DISTANCE =10^2 + 10^2 =100 + 100 =200 THEREFORE DISTANCE = √(200) =√(5 * 5 * 2 * 2 * 2) = 10√2 DISTANCE BETWEEN ANY TWO POINTS WILL BE 10√2 UNITS.