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ΔABC is isosceles with AB=AC, P is mid point of BC. if PM is perpendicular to AB and PN is perpendicular to AC, show that PM=PN. View the attached document

to get the figure. Also suggest me a simple way to give attachment of a figure

You may also prove by showing that triangles BPM and PCN are congruent.

1.Triangle ABC being isosceles, angles b and C are equal. 2.P being the mid-point, sides BP and PC are equal. 3.Angles BPM and CPN are equal, being equal to (90 - Angle B) and (90 - Angle C) respectively. Hence triangles are congruent and hence PM = PN.