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2014-09-03T10:51:52+05:30
I answered the above question in word format, kindly c the attachement file
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2014-09-03T17:08:42+05:30

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 \frac {(1+\frac{Cos\theta}{sin \theta}+\frac{Sin\theta}{Cos\theta})(sin\theta-cos\theta)}{\frac{1}{cos^3\theta} - \frac{1}{SIn^3\theta}} \\ \\ \\ \frac{(Sin\theta\ Cos\theta+Cos^2\theta+Sin^2\theta)(Sin\theta-Cos\theta)Sin^3\theta\ Cos^3\theta}{Sin\theta\ Cos\theta (Sin^3\theta - Cos^3\theta)} \\

 \frac{(Sin\theta\ Cos\theta+1)(Sin\theta-Cos\theta)Sin^2\theta\ Cos^2\theta}{(Sin\theta-Cos\theta)(Sin^2\theta+Sin\theta\ Cos\theta+Cos^2\theta)} \\ \\ \\ Cancelling\ corresponding\ terms\ in\ Nr\ and\ Dr,\ then \\

Sin^2\theta\ \  Cos^2\theta \\
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