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Root(1/cos^2fi+1/sin^2 fi)=root(sin^2fi+cos^2fi)/sin^2fi cos^2 fi

hence=  1/sinfi cos fi= 1/1/2sin2fi= 2 coec2fi
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hx for ur answer,... but could it be more in detail ??
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yaa ,... i got tht !! but i just wanred to check with me answer so,.. anyways thnk u
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Let  : rt(sec^2fi+cosec^2fi)=X
     =(sin^2fi+cos^2fi)/(sin^2fi cos^2fi)
     =1/(sin^2fi cos^2fi)
 X^2=sec^2fi cosec^2fi
 X = sec fi. cosec fi
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