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Let ABCD be a rhombus.With AC and BD are diagonals of it of length 16 and 32.
diagonals of rhombus bisect each other at right angle.

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Diagonal of a rhombus bisect each other at right angle
one of the side of a rhombus = square root of (8^2+15^2)
                                          =square root of(64+225)
                                           =square root of (289)
perimeter of arhombus=4(side)

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