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A man's age is three times the sum of the ages of his two sons. After 5 years, his age will be twice the sum of the ages of his two sons. Find the age of

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Let the Man's age be M years. Let the Sum of ages of both Children be C years.

Man's age M = 3 C = 3 times the sum of sons' ages. M+5 = Man's age after 5 years = 2 (C+10) ,as each child's age increases by 5 years. and their sum increases by 10 years.

So, M = 3 C M + 5 = 2 (C +10) = 2 C + 20

Substitute 1st equation in the 2nd.

3 C + 5 = 2 C + 20 C = 15 years M = 45 years

The mans' age now is 45 years and sum of children's age is 15 years now.

Age of 1st son x 2 nd son y man age 3x +3y after 5 years ....... 3x + 3y + 5 = 2(x + y + 10 ) 3x + 3y +5 = 2x + 2y +20 x + y = 15 man age = 3(x+y) = 3X 15 45