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Given a+b+c=5 and ab+bc+ac=10

a³+b³+c³-3abc=(a+b+c) (a²+b²+c²-(ab+bc+ca))

(a+b+c)²=(a²+b²+c²) +2(ab+bc+ac)
     5²    =(a²+b²+c²)+ 2(10)
    25    =(a²+b²+c²)+20

a³+b³+c³-3abc=(a+b+c) (a²+b²+c²-(ab+bc+ca))

1 5 1
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