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Ap=2,4,6 d=2 Sn=420 we have to find n Sn=n/2 (2a+(n-1)d)=420 a=2 n( 4 + (n-1) 2)=840 d-2 n(4 + 2n-2) =840 n( 2n+2) = 840 2n²+2n -840=0 n²+n-420=0 n=20,-21 since n is positive number of terms needed are 20 so if we take 20 terms of the AP=2,4,6 we could get the sum 420