Answers

2014-09-17T09:44:59+05:30
Equation of x varies inversely as square of y means
x=k/y^2
substituting y=3 and x=4
we get
4=k/3^2
4=k/9
multiplying both sides by 9
4*9=k
k=36
finding x when y=6
so substituting y=6 and k=36 in x=k/y^2
x=36/6^2
x=36/36
x=1
hence the value of x when y=6 is 1
 
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2014-09-17T13:01:40+05:30
X varies inversely as y^2 therefore X=d/y^2.therefore replace X=4 when y=3 therefore d= 36. Now replace k=36 and y= 6 therefore X=6
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