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Let the width of rectangle(b) = x m. then length(l) = (x+4) m. a/q, perimeter of rectangle = 40 m. or, 2(l+b) = 40 or, 2(x+4+x) = 40 or, 2(2x+4) =40 or, 4x+8 =40 or, 4x = 40-8 or, x = 32/4 x= 8 so, width(b) = x = 8 m. And, length(l) = x +4 = 12 m therefore its dimension is 12m×8m

Let the width of the rectangle be x given that the length is 4m more than its width so the length of the rectangle be x+4 And perimeter=40m perimeter of a rectangle is p=2(l+b) Replacing p=40,l=x+4 and b=x we get 40=2(x+4+x) 40=2(2x+4)

dividing both sides by 2 20=2x+4 adding -4 on both sides 2x+4-4=20-4 2x=16 dividing both isdes by 2 2x/2=16/2 x=8 Thus the width of the rectangle be 8m and the length of the rectangle be x+4=8+4=12m length of the rectangle be 12m