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1. initial velocity, u = 0 final velocity, v = 40 km/h = 11.11 m/s displacement, s = 10 m acceleration = a

Since it travels h/2 in last 1 second, the first h/2 is travelled in (t-1)second. h/2 = (1/2)×g×(t-1)² ⇒h = g×(t-1)²

also h = (1/2)×g×(t)²

from both equations (1/2)×g×(t)² = g×(t-1)² ⇒t²/2 = (t-1)² ⇒t²/2 = t² - 2t + 1 ⇒t²/2 -2t + 1 = 0 By solving, we get t = 3.414s (0.59s is not possible as it is less than 1 second)