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A square and an equilateral Δ have = perimeters. If the diagonal of the square is 12√2 cm, then find the area of the Δ.



Diagonal of the square =√2 a
⇒√2 a =12√2
so the perimeter of the square =4*12=48cm
perimter of the triangle is also 48 cm...

so each side of the triangle is 16cm
area of the eq. triangle =√3 a²/4
so the are of the triangle=√3*64=64√3 cm²
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