Answers

2014-09-19T21:38:19+05:30
3x+y=11
5x+4y=30
5x=30-4y
x=30-4y
      5-------------------------1
Putting the value of x in equation 2.
3(30-4y/5)+y=11
90-12y+5y=55                [By taking L.C.M]
-7y=55-90
-7y=-35
y=-35/-7
y=5
putting the value of y in 1.
x=30-4(5)/5
x=30-20/5
x=10/5
x=2




 
 
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2014-09-19T21:39:21+05:30
5x+4y=30-----(1)
3x+y=11-------(2)
now multiplying equation (2) by -4
-12x-4y=-44-----(3)
to eliminate y add (1) and third equations
5x-12x+4y-4y=-44+30
-7x=-14
dividing both sides by -7
x=2
substituting x=2 in equation (2)
3x+y=11
3(2)+y=11
6+y=11
adding -6 on both sides
-6+6y=11-6
y=5
thus the values are x=2 and y=5

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