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By factorization we get
take 4 as common in first two terms and -3 as common in next two terms
take y+4 as common
by using the principle of zero products
4y-3=0  or  y+4=0
4y=3      or      y=-4
   y=3/4    or    y=-4
thus the values of x are 3/4 and -4
0 0 0
hey you have some mistake in last line
4y^2+13y-12=4y^2+16y-3y-12 = 4y(y+4)-3(y+4) 

The factors are (4y-3)(y+4)

 (4y-3)(y+4) = 0



the values of y are 3/4 and -4

0 0 0
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