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Δ Given that a straight line ax+by+c = 0 is always passe through the point (1,-2)
hence the value of x = 1 and y =-2
therefore from Eqn ,
                   a(1)+b(-2)+c = 0
                 ⇒ a-2b+c = 0
                 ⇒a+c = 2b
                  so, b= (a+c)/2
therefore a, b ,c are in A.P
0 0 0
Given the straight line ax+by+c=0 always passes through (1,-2) 
Hence x=1 and y=-2
now, a(1)+b(-2)+c=0
Hence a, b, c are in A.P

0 0 0
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