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1) A body is moving along a horizontal circular path with constant speed v. What is the change in its velocity when it describes an angle

? {answer should come 2v sin}

2) Particle A of mass M is revolving along a circle of radius R. Particle B of mass m is revolving in another circle of radius r. If they take the same time to complete one revolution, then the ratio of their angular velocities is {answer should come 1}

3) Two particles of masses M an m revolve in circular orbits of radii R and r. If the time periods of both the particles are equal, then the ratio of their linear speed is {answer should come }

4) The angular velocity of a wheel increases from 600 revolutions/minute to 2400 revolutions/minute in 10 seconds. The number of revolutions made during this time interval is {answer should come 250 revolutions}

5) A particle moves along a circle of radius 10 cm. If its linear speed changes from 4 m/s to 5 m/s in 1 second, then its angular acceleration will be {answer should come 10}

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1. refer to diagram.

Change in velocity ΔV = V₂ - V₁ vector subtraction. V1 and V2 are of same magnitude V but are inclined at angle Ф. The triangle formed by the three vectors is an Isosceles triangle. Draw a perpendicular bisector on to the vector V2 - V1. The angle is bisected.

Now magnitude of V2 - V1 = 2 * sin Ф/2 * hypotenuse = 2 V sin Ф/2

3. Let the time period of revolution of both masses be T. In time T, m travels a distance = 2 π r and M moves a distance 2 π R. So linear speed of m = 2π r / T linear speed of M = 2 π R / T Ratio = R/r

2. Let the time period of revolution of both masses be T. In time T mass m covers an angle of 2 π radians and M also covers an angle of 2π rad. angular speed = ω = 2π/T = same for both

4. Revolutions made = angle Ф rotated through in 10 seconds / 2π Ф = time duration * average angular speed = 10 * (ω₂ + ω₁) / 2 = 10 * [ (2400 + 600)/2 ] * (2π/60) rad = 500 π rad n = revolutions = 500π/2π = 250