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F = GMm R² M is the mass of the Earth m is the mass of the object R is the radius of the earth =6400km(given)

When object is kept on surface. W=F=GMm= 20 N R² When object is lifted to a certain height=R' = R+h = 2R h = R = 6400 km Now we have weight of the object is W' = F' = GMm (2R)² W' = (1/4).(GMm) R² =W 4 Now the weight of the object will be weight=20 4 W=5N

We know that F=Gm₁m₂/d² ⇒20N=Gm₁m₂/R²..............(i) given radius is 6400km=R the body is at 6400 above the level of ground. so total radius becomes 2R ⇒F=Gm₁m₂/(2R)² F=Gm₁m₂/4R² F=Gm₁m₂/R²*1/4 F=20N*1/4...(from eqn (i)) F=W=5N