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Car A takes 1 hour less than car B to cover a distance of 132 km. if the average speed of car A

is 11km/hr more than that of car B, formulate the quadratic equation




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Let average speed of car B = x km/h
      average speed of car A = (x+11) km/h

To cover 132 km, 
time taken by car B = 132/x hours
time taken by car A = 132/(x+11) hours

 \frac{132}{x}  \frac{132}{x+11} = 1
⇒132( \frac{1}{x}  \frac{1}{11+x} ) = 1
⇒132( \frac{-x+(x+11)}{x(x+11)} ) = 1
⇒132( \frac{11}{x(x+11)} ) = 1
 \frac{132(11)}{x^2+11x} = 1
⇒x² + 11x = 1452
⇒x² + 11x -1452 = 0
1 5 1
the avg speed of B be x
then the avg speed of A=x+11

the distance covered=132 km
 time taken by A=132/(x+11)
time taken by B=132/x
 ATQ ,
  \frac{132}{x} - \frac{132}{x+11} =1
solving this we will get
which is the required quadratic eqn

0 0 0
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