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A mixture contains 0.2 g of oxy and 0.4 g of carbon di oxide . The ratio of oxygen atoms present in oxygen to that in carbon di oxide

(1) 3:6 (2) 11:8 (3) 3:4 (4) 11:16



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Weight of oxygen = 0.2g
mole of oxygen = 0.2/32
no. of oxygen molecule = (0.2/32)A  (A=avogadro's number)
no. of oxygen atom = 2X(0.2/32)A  (one oxygen molecule has 2 atoms)

weight of carbon dioxide = 0.4g
moles of carbon dioxide = 0.4/44
no.of carbon dioxide compound = (0.4/44)A
no. of oxygen atom = 2 X(0.4/44)A (one carbon dioxide compound has 2 oxygen atoms)

ratio = [ 2X(0.2/32)A ] / [ 2 X(0.4/44)A ] = 11/16
3 4 3
Thank you .you are great in chemistry
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