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2014-10-03T22:23:34+05:30

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Let the density of the body =  p kg/m³
                          its volume = v m³
weight of body in a medium = (density of body-density of medium)×v×g

Case:1
weight in air = 160g = 0.16kg × g m/s²   (g=acceleration due to gravity)
density of air ≈ 0
Thus
0.16×g = (p-0)vg
⇒v = 0.16/p

Case:2
weight in water = 130g = 0.13kg × g m/s²
density of water = w kg/m³
Thus 
0.13 × g = (p - w)vg
⇒p-w = 0.13/v
⇒p-w = 0.13/(0.16/p)
⇒p-w = 0.13p/0.16
⇒p-w = 13p/16
⇒p - 13p/16 -w = 0
⇒3p/16 = w
⇒p = 16w/3

Case:3
weight in oil = 136g = 0.136kg × g m/s²
density of oil = d kg/m³
Thus 
0.136 × g = (p - d)vg
⇒0.136 = (p-d)v
⇒0.136 = (p-d)(0.16/p)

⇒0.136 = (0.16) \frac{p-d}{p}

⇒ 0.136/0.16 = 1- \frac{d}{p}

⇒0.85 = 1 - \frac{d}{16w/3}

⇒0.85 = 1 -  \frac{3}{16}  \frac{d}{w}

But accrding to defination of specific gravity, specific gravity of oil =  \frac{d}{w}

⇒  \frac{3}{16} \frac{d}{w} = 1 - 0.85

⇒  \frac{3}{16} \frac{d}{w} = 0.15 

 \frac{d}{w}  \frac{16}{3}  ×0.15

 \frac{d}{w}  \frac{16}{3} * \frac{15}{100}

 \frac{d}{w} = 0.8

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2014-10-03T23:26:04+05:30

This Is a Certified Answer

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Specific gravity of a medium = density of the medium / density of water 
         = ρ = ρ_{medium} / ρ_{water}

= \frac{weight\ in\ air - weight\ in\ medium}{weight\ in\ air - weight\ in\ water}\\ \\= \frac{W_{air}-W_{oil}}{W_{air}-W_{water}} \\ \\= \frac{160-136}{160-130} =\frac{24}{30} = 0.80 \\


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