Answers

2014-10-04T21:10:06+05:30
∫ sin^-1(x) / √(1 - x^2) dx

∫ sin^-1(x) * (1 / √(1 - x^2)) dx ===> u-sub

u = sin^-1(x)
du = (1 / √(1 - x^2)) dx

∫ u * du

u^2/2 + C

(1/2) * ( sin^-1(x) )^2 + C
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