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Five years hence , father's age will be three times the age of his son. Five years ago , father was seven times as old as his son . Find their present




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Let father's age = x
son's age = y

Five years hence, age of father = x+5 
                                 age of son = y+5
So (x+5) = 3(y+5)
⇒ x =3y+10

Five years ago, age of father = x-5 
                                 age of son = y-5
So x-5 = 7(y-5)
⇒3y + 10 - 5 = 7y - 35
⇒ 4y = 40
⇒y = 10  <<<<<<<<son's age
   x = 3y +10 = 40 <<<<<<father's age

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