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many numbers can  be formed-





951370 etc.

make sure that the number ends with 0 the it is divisible by 10

0 0 0

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For a number to be divisible by 10, its unit digit should be 0.
So we can arrange rest 5 numbers (1,3,5,7,9) in the five places without repeating.
It can be done in ⁵P₅ ways.

⁵P₅ =  \frac{5!}{(5-5)!} =  \frac{5!}{0!}= \frac{120}{1} = 120  numbers
0 0 0
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