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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let the tens digit be x and the units digit be y.Then the two-digit number is (10x + y). Given: Two-digit number = 4 times sum of its digits 10x + y = 4(x + y) ⇒ 10x + y = 4x + 4y ⇒ 6x = 3y x = y/2.... (1) Given: Two-digit number = Twice the product of its digits ⇒ 10x + y = 2(xy) ⇒10x + y – 2xy = 0 …(2) substituting x= y/2 from equation (1) and equation (2) we get 10 * y/ 2 + y - 2 * y / 2* y = 0 ⇒5y + y – y2 = 0 ⇒y2 – 6y = 0 ⇒y (y – 6) = 0 ⇒ y = 0 or y – 6 = 0 We reject y = 0 because then x would also be zero. Therefore, y = 6 Substituting this value of y in equation 1, we get x = 6/ 2 = 3 Hence required number is (10 × 3 + 6) = 36