A monkey of mass 40 kg climbs on a rope which can stand a maximum tension 600 N. In which of the following cases will the rope break? The monkey

(a) climbs up with an acceleration of 6m/s2
(b) climbs down with an acceleration of 4m/s2
(c) climbs up with a uniform seed of 5m/s
(d) falls down the rope freely under gravity.

Take g = 10m/s2 and ignore the mass of the rope.

CLASS - XI PHYSICS (Laws of Motion)

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Answers

  • Brainly User
2014-10-10T22:58:53+05:30
(a)    F = T – mg
ma = T – mg
T = ma + mg  
= m(a + g)
 
= 40(10 +6)
 
=640N

This is greater than the max. tension which the rope can withstand. Hence the rope will break.

(b)F = mg – T
ma = mg – T
T = mg - ma  
=m(g - a)
         
= 40(10 - 4)
 
= 240N

This is lesser than the max. tension which the rope can withstand. Hence the rope will not break.

( c) F = T – mg   
ma = T – mg
      
T = ma + mg
         
 = m(a + g)
           
= 40(0+ 10)
          
=400N

This is greater than the max. tension which the rope can withstand. Hence the rope will not break.

( d) F = mg – T
ma = mg – T
T = mg - ma  
=m(g - g)
 
= 0N
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