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A bullet fired in to a fixed target loses half of it's velocity after penetrating 3 cm . How much further will it penetrate before coming to rest assuming

that it faces constant resistance to motion


X = 3cm 
v = u/2
v^2 = u^2 + 2ax
on solving this u will get,
a = -u^2/8    ......... (1)
after penetrating,
v = 0
initial velocity = u/2

v^2 = u^2 + 2ax
0 = 1/4 - (2/8)x
x = 1cm 
so it will penetrate 1cm before coming to rest
0 0 0
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