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Force of 16N and 12N are acting on a mass of 200kg in mutually perpendicular directions. Find the magnitude of the acceleration produced?

CLASS - XI PHYSICS (Laws of Motion)


Acceleration will be opp to the direction from where 16N force will be applied
and the magnitude will be 12/200=0.06m/s^2.
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16N and 12N are acting in mutually perpendicular direction.
So resultant force = √(16² + 12²) = √256+144 = √400 = 20N
mass of body = 200 kg

acceleration = net force/mass = 20/200 = 0.1 m/s²
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