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Lock of mass 10kg is sliding on a surface inclined at a angle of 30o with the horizontal. Calculate the acceleration of the block. The coefficient of

kinetic friction between the block and the surface is 0.5

CLASS - XI PHYSICS (Laws of Motion)


A=g[sinθ - μcosθ] Answer: 0.669m/s for g=10
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See diagram.
resolve mg = weight of block  in two directions - along the plane and perpendicular to the plane.

    N = mg Cos Ф             as there is no acceleration perpendicular to the incline

    m a = mg Sin Ф - μ N = mg (Sin Φ - μ Cos Φ)
       a = g (Sin Φ - μ Cos Φ) = 9.81 (Sin 30 - 0.5 Cos 30)

     acceleration of the block down the plane  = 9.81 (1/2 - 0.5 √3/2)
                = 0.657 meters/sec²

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