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A particle is thrown upwards. It attains a height (h) after 5 seconds and again after 9s comes back. What is the speed of the particle at a height h?

CLASS - XI PHYSICS (Kinematics)


H=ut + 1/2at∧2 h=u5 - 1/2g5∧2=u9 - 1/2g9∧2 You get speed at height(h)=68.6m/s for g=9.8m/s∧2
1 5 1
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