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A stone is dropped from the top of a cliff and is found to ravel 44.1m diving the last second before it reaches the ground. What is the height of the

cliff? g = 9.8m/s2

CLASS - XI PHYSICS (Kinematics)



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Initial velocity(u ) = 0
using formula for displacement in t th second


⇒ 44.1 = 1/2 x 9.8  (2t-1)
⇒(44.1 x 2)9.8 + 1 = 2t
⇒10/2 = t
⇒t = 5 sec

so using equation


⇒s = 0 + 1/2 x 9.8 x (5)²
⇒s = 4.9 x 25
⇒s = 122.5 m
so total height = 122.5 ANSWER

1 5 1
It is asked the height of the cliff so we must add the last distance covered too
i mean that if we don't add that we can't get the cliff's height right?
oh ok ok i think i need to edit it but i can't get the option for editting
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