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Let the number 'a' be the common divisor for the given numbers
so the numbers are 2a , 3a and 4a.
it is given that the sum of the cubes of 2a , 3a and 4a is 33957
so 99 times the cube of 'a' is 33957
⇒cube of a is 343
a = 7
so the numbers are 14 , 21 , 28.
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Let the numbers be 2x , 3x and 4x

(2x)³+(3x³)+(4x)³ = 33957
8x³+27x³+64x³= 33957
x³= 33957/99
x= 7

so the numbers are 14,21,28
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