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Let cost of each orange = Rs. x cost of each banana = Rs. y Cost of 20 oranges and 30 bananas = 20x+30y So 20x+30y = 280 ⇒ 2x + 3y = 28

if cost of each orange is doubles, cost of each orange = 2x cost of 30 oranges and 40 bananas = 30(2x) + 40y = 60x+40y thus 60x+40y = 540 ⇒6x + 4y = 54 Solving the two equations we get, x = 5 and y = 6. So cost of each orange = Rs. 5.

Let the cost of each orange be Rs x Cost of each banana = Rs y

Cost of 20 oranges and 30 bananas = 280 ⇒20x+30y = 280 Dividing both sides by 10 ⇒ 2x + 3y = 28 ........(1)

Cost of each orange is doubled. Now, cost of orange = Rs 2x Cost of 30 oranges and 40 bananas is Rs 540 60x + 40y = 540 Dividing both sides by 20 3x + 2y = 27 .......(2)