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I am thinking about two numbers having the same two digits. the sum of the two digits is 9 and the difference of the two numbers is 27. find the two



Let the two digits be a and b
then two numbers will be 10a+b and 10b+a
from the problem,
a+b=9 and 10a+b-(10b+a)=27
take a+b=9 as 1st equation
by solving 10a+b-(10b+a)=27 we will get
a-b = 3  take this as 2nd equation
now add 1and 2 equations
2a=12 and a =6 then the value of b will be 3
therefore the numbers are 63 and 36
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Let 2 nos be x,y.                            x+y=9;x=9-y.                                                                                         now x-y=27;                                                                                                         9-y-y=27                                (bcoz  x=9-y)                                                        2y= -18                                                                                                                y= -9   there4 x=18

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