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Ask your question hereA testube loaded with lead shots floats to the mark X the testube along with shots weigh 25g. When the testube is floated with

brine,5g of lead shots were added to make it float upto mark X. Find the relative density (RD) of brine.



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You haven't given the first liquid. Since relative density is required, i am assuming it to be water.
Since in both cases the test tube floats upto mark X, the volume displaced in case of brine and water are same. 
Let density of water = w
density of brine = b
Relative density of brine = b/w

So Volume displaced in water = Volume displaced in brine

⇒  \frac{25}{w*g} = \frac{30}{b*g}

 \frac{b}{w}= \frac{30g}{25g}  = \frac{30}{25}

 \frac{b}{w}= \frac{30}{25}=1.2

Thus relative density of brine is 1.2
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