Answers

2014-10-19T10:29:16+05:30
(2014²-2020)(2014²+4028-3)(2015)÷(2011)(2013)(2016)(2017)

(4056196-2020)(4056196+4028-3)÷[(2011)(2013)][(2016)(2017)]

(4054176)(4060221)÷(4048143)(4054176)

33168613823785440÷16460850532896

= 2015
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It could be done by writing numeratoras (2014^2 - 2014 - 6)(2014^2 - 2x2014 -3)x2015 .first two brackets are equal to (2011)(2016) and (2013)(2017) which cancel out with the denominator. hence ans = 2015
  • Brainly User
2014-10-19T15:22:52+05:30
                                       calculation is give below                                   


(2014²-2020)(2014²+4028-3)(2015)   ÷       (2011)(2013)(2016)(2017)

(4056196-2020)(4056196+4028-3)    ÷       [(2011)(2013)][(2016)(2017)]

(4054176)   (4060221)               ÷                           (4048143)(4054176)

33168613823785440÷1646085053289= 2015
                                                                        plz mark it best       

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