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Let side of square = a radius of circle = r perimeter of square = 4a perimeter of circle = 2πr sum = 4a+2πr = K ⇒4a = K-2πr ⇒a = (K-2πr)/4

area of square = a² = ((K-2πr)/4)² = (K-2πr)²/16 area of circle = πr² sum of areas, S = πr² + (K-2πr)²/16

P(circle) =2pie r p(square)=4s a.t.q. 2pie r+4a=k pie r2 +a2 (given that) 2r=a assuming the value of r=1 then, 2*22/7*1+8(1)=100/7 (sum of peri. ) 22/7*(1)square+4(1)square=50/7 so here area is minimum