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An aquarium is made of glass that has the density of 2500

kg/m³ and having the thickness of 4mm. the aquarium has the length of 1 meter, the breadth of 40 cm and the height of 25 cm. the aquarium is placed on a wooden table. Somebody then filled it with water. The volume of the water is 60 liter and its density 1000 kg/m³. If we are using the gravitational acceleration of 9,8 m/s² ; decide :

a. the height of the water in the aquarium

b. the weight of the aquarium when it is still empty

c. the weight of the aquarium when It is already filled with water

d. the pressure caused by the aquarium with water to its table

e. if there’s a turtle living at the bottom of the aquarium, how big is the hydrostatic pressure received by the turtle

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A. height of water in the aquarium = = volume of water filled / area of bottom of aquarium = 60, 000 cm³ / (100 cm * 40 cm) = 15 cm If the length and breadth given are the dimensions outside (external), then height = 60, 000 cm³ / [ (100 - 2 * 0.4) cm * (40 - 2 * 0.4) cm ] = 15.43 cm

b) if given dimensions are internal dimensions of aquarium. then: (there is no top lid)

Volume of the glass material in the aquarium = 4, 461.056 cm³ Weight of the aquarium = 4, 461.056 cm³ * 2.5 g/cm³ * 980 cm/sec² = 109, 29, 587.2 dynes = 109.30 Newtons

c) Weight of 60 liters of water = 60 kg Total weight of aquarium with water = 169.30 newtons

d)

Pressure = Force on the table / Area of exterior at the bottom of aquarium = 169.30 Newtons / (1.08 m * 0.48 m) = 326.581 Pa or N/m² Here we are not considering the weight of atmosphere above aquarium.

e) Hydrostatic pressure on the turtle = weight of water column at the bottom of aquarium = 15.43 cm of water column * 1 gm/cm³ * 980 cm/sec² = 15121.4 dyne = 0.151214 Pa If the standard atmospheric pressure (of air above water level ) is to be added in addition to the hydrostatic pressure then, 1 atm is to be added.

And does the aquarium contain a lid on top of it?